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2012-01-14T07:03:28 yeah 2012-01-14T07:03:38 wait which? what I pasted? 2012-01-14T07:03:49 thats the solution they gave, so I presume it's correct :P 2012-01-14T07:04:34 mmm 2012-01-14T07:04:39 you're missing something 2012-01-14T07:05:03 oh? 2012-01-14T07:06:43 scalar v. vector 2012-01-14T07:06:44 i thought you wrote it 2012-01-14T07:07:04 mcstar: no 2012-01-14T07:07:10 my version was entierly wrong 2012-01-14T07:07:15 thats the smart way to do it 2012-01-14T07:07:36 scalar is distance 2012-01-14T07:07:44 vector is distance and direction 2012-01-14T07:07:46 I've got to go now, but if you give me your source later I can test it? 2012-01-14T07:07:52 combine that with pythagorean 2012-01-14T07:08:10 conor_f: hm? 2012-01-14T07:08:18 i gave you mine 2012-01-14T07:08:19 mcstar make sense? 2012-01-14T07:08:31 no 2012-01-14T07:08:35 what scalar/vector? 2012-01-14T07:08:39 oh yeah, sorry, I forgot mcstar I'll find it later so 2012-01-14T07:08:49 just came on to let you know the smart way :P 2012-01-14T07:08:53 k 2012-01-14T07:08:55 I'll ttyl 2012-01-14T07:08:55 thx 2012-01-14T07:09:08 if you travel up 5points, and over 4 points 2012-01-14T07:09:14 how far are you from where you started 2012-01-14T07:09:19 3 points 2012-01-14T07:09:28 but how far have you traveled 2012-01-14T07:09:33 9 points 2012-01-14T07:09:48 starting to see the relation? 2012-01-14T07:09:51 no 2012-01-14T07:10:15 first of all, is this related to the problem conor_f pasted? 2012-01-14T07:10:26 *** theskumar has joined #aichallenge 2012-01-14T07:10:37 calc, 101 you solve for the lengths of each dimension, or you solve for the area within the dimensions 2012-01-14T07:10:38 what problem is this? 2012-01-14T07:10:56 btw a scalar is something that remains the same wrt coordinate transformations 2012-01-14T07:11:02 no 2012-01-14T07:11:03 it is an invariant 2012-01-14T07:11:09 that's an eigenvector 2012-01-14T07:11:28 o_O 2012-01-14T07:11:31 wtf 2012-01-14T07:11:42 a scalar is the inverse of a vector... because you use integration or differentiation to solve for the other 2012-01-14T07:11:48 lol 2012-01-14T07:11:51 ... 2012-01-14T07:12:13 sigh: conor_f had a programming olympiad problem, thats the official solution for that 2012-01-14T07:12:25 *** theskumar_ has joined #aichallenge 2012-01-14T07:12:48 Guest61192: youre way off 2012-01-14T07:12:49 *** theskumar has quit IRC (Read error: Connection reset by peer) 2012-01-14T07:12:51 mcstar: i see, just counting paths through a grid? 2012-01-14T07:12:52 *** theskumar_ is now known as theskumar 2012-01-14T07:12:53 or trolling us... 2012-01-14T07:12:55 *** mikewintermute has joined #aichallenge 2012-01-14T07:12:55 mcstar 2012-01-14T07:13:04 *** conor_f has quit IRC (Ping timeout: 245 seconds) 2012-01-14T07:13:05 link me the original question 2012-01-14T07:13:21 I'll write up some c++ or lisp 2012-01-14T07:13:33 sigh: two cows starting from opposite corners of a 5x5 grid, needs to meet at the same tile, while self-avoidingly stepping on every open tile 2012-01-14T07:13:45 there can be obstacles too 2012-01-14T07:13:47 *** mikewintermute has quit IRC (Client Quit) 2012-01-14T07:13:48 at any tile 2012-01-14T07:14:03 how many paths are possible for a given set of obstacles 2012-01-14T07:14:32 do the cows have to move every turn? 2012-01-14T07:14:44 yea 2012-01-14T07:14:45 they move simultaneously at every turn 2012-01-14T07:14:59 because you're solving for possible combinations 2012-01-14T07:15:21 cool, thanks... just checking I understood the problem correctly :) 2012-01-14T07:15:29 solve this with a karnaugh map 2012-01-14T07:15:34 ... 2012-01-14T07:15:43 and a 2x2 grid 2012-01-14T07:22:44 *** dvladim has quit IRC (Ping timeout: 240 seconds) 2012-01-14T07:45:23 @later tell conor_f http://mathbin.net/87293 i wrote up quickly a solution to your last problem, i hope it helps 2012-01-14T07:45:23 mcstar: I think that worked... 2012-01-14T07:46:24 arn 2012-01-14T07:46:25 darn 2012-01-14T07:47:50 @later tell conor_f dont pay attention to the first paste, it has a typo 2012-01-14T07:47:50 mcstar: Ready to serve, my lord. 2012-01-14T07:54:40 *** dr- has quit IRC (Ping timeout: 240 seconds) 2012-01-14T08:02:20 *** mleise1 has quit IRC (Ping timeout: 240 seconds) 2012-01-14T08:14:44 *** ruser has quit IRC (Ping timeout: 240 seconds) 2012-01-14T08:15:41 u can run opensouse bots onhttp://tcpants.com/ranking ? 2012-01-14T08:22:08 *** ruser has joined #aichallenge 2012-01-14T09:03:13 *** smjms has joined #aichallenge 2012-01-14T09:03:47 *** Kurnevsky has quit IRC (Quit: Instantbird 1.0) 2012-01-14T09:04:58 *** kire has joined #aichallenge 2012-01-14T09:05:22 gara 2012-01-14T09:07:54 *** conor_f has joined #aichallenge 2012-01-14T09:07:54 *** conor_f has quit IRC (Client Quit) 2012-01-14T09:08:07 did someone just post 2012-01-14T09:08:13 the answer I gave 2012-01-14T09:08:27 off of google 2012-01-14T09:08:31 spit 2012-01-14T09:11:06 *** Guest61192 is now known as Colors 2012-01-14T09:11:51 I don't even really know math, and I still knew a better method 2012-01-14T09:12:29 now if someone can incorporate karnaugh maps... to reduce the obstacles 2012-01-14T09:23:13 *** Kurnevsky has joined #aichallenge 2012-01-14T09:24:55 I think I deserve to post this http://mathbin.net/87293 2012-01-14T09:28:28 Have we taken our meds today? 2012-01-14T09:29:02 no 2012-01-14T09:29:11 no your right we haven't 2012-01-14T09:29:57 you're 2012-01-14T09:30:13 pairofdice... you can tell me, I was right, right? 2012-01-14T09:33:26 pairofdice: i thought he left 2012-01-14T09:33:56 leave the net? nevveerr 2012-01-14T09:34:08 that's what the backups are for 2012-01-14T09:34:25 its a pun on your "right" 2012-01-14T09:34:37 dpm 2012-01-14T09:34:40 don't get it 2012-01-14T09:34:48 *** avdg has joined #aichallenge 2012-01-14T09:41:40 Colors: so what is this about? why are you pasting my links? are you trolling or what? 2012-01-14T09:43:11 *** choas has quit IRC (Ping timeout: 252 seconds) 2012-01-14T09:43:32 mcstar... why'd you post that link? 2012-01-14T09:43:49 none of your business 2012-01-14T09:43:55 wasnt addressed to you 2012-01-14T09:44:13 but... you basically wrote up my solution... using latex 2012-01-14T09:44:17 no? 2012-01-14T09:44:25 what do you mean? 2012-01-14T09:44:28 who the f are you? 2012-01-14T09:45:12 (07:07:35 AM) Guest61192: scalar is distance 2012-01-14T09:45:12 (07:07:44 AM) Guest61192: vector is distance and direction 2012-01-14T09:45:12 (07:07:46 AM) conor_f: I've got to go now, but if you give me your source later I can test it? 2012-01-14T09:45:12 (07:07:52 AM) Guest61192: combine that with pythagorean 2012-01-14T09:45:18 see way before your post 2012-01-14T09:46:16 i dont even know what are you refrring to 2012-01-14T09:46:48 i was talking with conor about something, and you came up with this 2012-01-14T09:46:53 why? 2012-01-14T09:46:55 mathbin 2012-01-14T09:47:22 ? 2012-01-14T09:48:01 http://mathbin.net/87293 2012-01-14T09:48:07 you posted that for what problem 2012-01-14T09:48:07 why would you say: "scalar is distance vector is distance and direction" when we are talking about some algorithmic problem? 2012-01-14T09:49:12 Colors: did you talk to conor before? 2012-01-14T09:50:28 im wasting my time with some troll... 2012-01-14T09:50:46 heh 2012-01-14T09:51:39 Welcome to Internet 2012-01-14T09:51:47 you know what originally made me thinking of using such basic trig, the greeks method of exhaustion... to solve for the area of a circle 2012-01-14T09:52:11 A: using triangles B: solving for every small increase of area from a triangle to a circle 2012-01-14T09:53:15 giving you many permutations... that you would sum and derive the constant pi 2012-01-14T09:53:27 same concept still using triangles 2012-01-14T09:53:37 only with a much simpler geometry... a square 2012-01-14T09:59:03 "you posted that for what problem" -> obviously you didnt read the paste, thx, it is the solution to a physics problem which involved a point mass sliding frictionless down a free wedge 2012-01-14T09:59:43 Colors: it has nothing to do with cicles greeks, pi, cows, algorithms, and you 2012-01-14T10:00:13 tsk tsk 2012-01-14T10:01:52 http://www.eserc.stonybrook.edu/wise/HSfall98/slide4a.html 2012-01-14T10:02:16 read up you RISC 2012-01-14T10:02:52 reduced instruction set cpu? 2012-01-14T10:03:03 don't take that literally 2012-01-14T10:03:51 very imformative link for elementary school students 2012-01-14T10:04:39 I'm sorry I made it too simple for even you 2012-01-14T10:06:19 I just thought, something like http://theory.stanford.edu/~amitp/GameProgramming/AITechniques.html would be a little over kill 2012-01-14T10:06:53 i didnt find much use for amit's collection for aichallenge 2012-01-14T10:07:40 Colors: still, do you understand that there are two separate problems here? 2012-01-14T10:08:15 and they both can be solved using the same exact arithmetic 2012-01-14T10:08:34 what are you solving for with the physics equations? 2012-01-14T10:08:50 did you read it? 2012-01-14T10:08:57 slope yea? 2012-01-14T10:09:03 if you did you know 2012-01-14T10:09:09 in relation to force 2012-01-14T10:09:13 im not solving "for the slope" 2012-01-14T10:09:28 there are 2 bodies 2012-01-14T10:09:31 with mas m and M 2012-01-14T10:09:34 mass* 2012-01-14T10:09:53 these accelerate when the system is released 2012-01-14T10:10:02 the solution is this acceleration 2012-01-14T10:10:17 or you can do whatever with it afterwards, compute trajectories whatever 2012-01-14T10:14:43 so if force = mass * acceleration 2012-01-14T10:15:15 and acceleration is the change in distance per second ^ 2? 2012-01-14T10:15:55 so if what? 2012-01-14T10:16:30 then calculating the slope of a triangle which is also the hypotenuse... as distance changes 2012-01-14T10:16:55 the slope is given 2012-01-14T10:16:55 then what it you'd be doing for both problems is "X is the distance of the tip of the right angle triangle from the origo, x is the distance of the point mass from X, in the x direction, and y is the distance of the point mass from the ground, in the y direction 2012-01-14T10:16:55 so the coordinate of the point mass in the x direction from the origo is x+X " 2012-01-14T10:17:35 you dont need to quote what i wrote 2012-01-14T10:19:14 scalar is your distance, the slope, the hypotenuse.... and the vector is length + width, x + y , delta(x) / delta(y) 2012-01-14T10:20:17 if you put that on a grid with discretized coordinates... you get points instead of lines... but the same applies 2012-01-14T10:23:33 *** dr- has joined #aichallenge 2012-01-14T10:24:53 in calc... what's one of the first things you learn... 2012-01-14T10:25:04 integrals and derivatives 2012-01-14T10:25:51 on a graph... one gives you a line or slope or curve 2012-01-14T10:26:05 the other gives you the area underneath 2012-01-14T10:26:30 jesus 2012-01-14T10:28:47 *** Dici_ has joined #aichallenge 2012-01-14T10:28:47 *** dici has quit IRC (Disconnected by services) 2012-01-14T10:28:51 *** Dici_ is now known as dici 2012-01-14T10:31:09 ... 2012-01-14T10:31:37 ... 2012-01-14T10:31:45 ... 2012-01-14T10:31:47 ... 2012-01-14T10:31:56 sigh: what are you awake? 2012-01-14T10:32:00 why* 2012-01-14T10:32:13 why can't I be awake? :( 2012-01-14T10:32:25 it's late:P 2012-01-14T10:32:37 why are you awake? 2012-01-14T10:32:50 just woke up 2012-01-14T10:32:54 ehe 2012-01-14T10:32:55 haha 2012-01-14T10:34:00 *shrug* I haven't gone to sleep yet :P 2012-01-14T10:34:11 i wonder if that path counting problem could be useful for a tron bot 2012-01-14T10:34:46 sort've 2012-01-14T10:35:02 I don't think so, since you are essentially enumerating all the paths 2012-01-14T10:35:08 the goal is different... you're objective is to corner the opponent 2012-01-14T10:35:13 is it that expensive to count? 2012-01-14T10:35:20 i guess so :P 2012-01-14T10:36:03 the first thing you do in tron... is try and gain the larger area 2012-01-14T10:36:18 so you cut the area somewhere close to half or a half of a half 2012-01-14T10:37:01 i know that 2012-01-14T10:37:15 i did write a bot for the tron contest 2012-01-14T10:37:34 something, I thought of that's unique for the path counting problem 2012-01-14T10:37:39 cows right? 2012-01-14T10:38:10 that... each coordinate can hold 2 states 2012-01-14T10:38:22 allowing for a boolean grid 2012-01-14T10:38:38 0 if you can move to that x, y coordinate 2012-01-14T10:38:59 1 if you've been their already, or 1 if there is an obstacle 2012-01-14T10:39:01 right? 2012-01-14T10:39:05 that's... exactly the solution that conor_f posted? 2012-01-14T10:39:30 because of that... you can use a karnaugh map to reduce the grid 2012-01-14T10:39:54 I don't think you know what you are talking about 2012-01-14T10:39:56 but ok 2012-01-14T10:39:58 I didn't even bother to look at his code 2012-01-14T10:40:01 *** choas has joined #aichallenge 2012-01-14T10:40:30 you don't bother to look at much of anything 2012-01-14T10:43:10 *** u__ has joined #aichallenge 2012-01-14T10:43:15 to vars 2012-01-14T10:43:21 two* 2012-01-14T10:43:52 im back 2012-01-14T10:44:03 im willing to feed it further 2012-01-14T10:44:26 !A and B or A and !B or A and B = Y 2012-01-14T10:44:44 why? 2012-01-14T10:45:09 because 2012-01-14T10:45:20 but why? 2012-01-14T10:45:46 "and the vector is length + width" 2012-01-14T10:45:53 that is the number of combinations you get from 2 bits 2012-01-14T10:46:02 thats gonna revolutionize math 2012-01-14T10:46:14 01 10 11 2012-01-14T10:46:50 lol 2012-01-14T10:46:52 it's total distance as opposed to displacement 2012-01-14T10:47:53 the above boolean equation simplifies to A or B = Y 2012-01-14T10:48:18 displacement is a proper vector, distance isnt 2012-01-14T10:48:35 now is that not a major reduction 2012-01-14T10:48:53 displacement is a scalar 2012-01-14T10:49:02 btw 2012-01-14T10:49:09 you are quite incorrect 2012-01-14T10:49:13 cheers 2012-01-14T10:49:52 woops 2012-01-14T10:49:53 antimatroid: still awake? 2012-01-14T10:49:54 your right 2012-01-14T10:49:58 ^_^ 2012-01-14T10:50:04 *** raemde_ has quit IRC (Ping timeout: 240 seconds) 2012-01-14T10:50:53 yeah 2012-01-14T10:51:05 you're 2012-01-14T10:51:18 god, turning off auto txt replacement 2012-01-14T10:51:45 antimatroid: hm, we are tied on PE 2012-01-14T10:51:54 :P 2012-01-14T10:51:57 antimatroid: look up #66 2012-01-14T10:52:03 very interesting problem 2012-01-14T10:52:08 try to solve it wo wikipedia 2012-01-14T10:52:30 (i did it in mathematica, so i dont consider mine a proper solution, and looking for a better) 2012-01-14T10:52:56 *** raemde has joined #aichallenge 2012-01-14T10:53:03 antimatroid might know the math already 2012-01-14T10:53:09 might 2012-01-14T10:53:12 might not :) 2012-01-14T10:53:35 i'm not familiar with diophantine equations if that's what you mean 2012-01-14T10:53:46 but you did learn about them 2012-01-14T10:53:47 othewise i'll play around when i'm not half asleep 2012-01-14T10:53:50 didnt you? 2012-01-14T10:54:24 im sure my mathematician friend had some number theoretical class 2012-01-14T10:54:42 i mean, in the standard curriculum 2012-01-14T10:55:22 ofc you dont have to solve it right now 2012-01-14T10:57:27 sigh: i hypothesize, that some succesive approximation scheme exists 2012-01-14T10:57:30 am i right? 2012-01-14T10:57:34 yes 2012-01-14T10:57:55 do you know what you are approximating? 2012-01-14T10:58:08 *** raemde_ has joined #aichallenge 2012-01-14T10:58:28 *** raemde has quit IRC (Ping timeout: 268 seconds) 2012-01-14T11:01:50 can someone help me unlock my calculator? 2012-01-14T11:10:17 i think i have a way that might do it 2012-01-14T11:10:21 no idea if its optimal 2012-01-14T11:10:35 efficiency wise 2012-01-14T11:13:29 antimatroid: this takes too long: sortBy (flip compare) [head [x|x<-[1..d], (x^2-1)`mod`d==0, issqr$(x^2-1)`div`d] | d <- [2..1000], not $ issqr d] 2012-01-14T11:13:59 me is bad with haskell 2012-01-14T11:14:41 I want F = {(x, y) : x^2-1 = ky^2 for some k \in Z^+} 2012-01-14T11:14:53 yes 2012-01-14T11:15:08 k=d 2012-01-14T11:15:29 in my notation: x^2-1 is a multiple of D 2012-01-14T11:15:36 x^2-1=k*D 2012-01-14T11:16:04 so k=y^2 2012-01-14T11:26:45 *** smiley1983 has quit IRC (Quit: leaving) 2012-01-14T11:31:52 what happens with D=4? 2012-01-14T11:31:57 there's just no solution? 2012-01-14T11:32:22 "It can be assumed that there are no solutions in positive integers when D is square." 2012-01-14T11:32:34 :P 2012-01-14T11:32:40 somehow i never read that line 2012-01-14T11:33:46 *** Chris_0076 has joined #aichallenge 2012-01-14T11:34:04 if D is square then you can factor the sum into two integers 2012-01-14T11:34:49 then you are solving fairly trivial equations :P 2012-01-14T11:35:27 or... square the other side of the = 2012-01-14T11:39:03 Colors: are you a markov text generator? 2012-01-14T11:40:17 I'm Schrödinger's cat 2012-01-14T11:41:02 schrodingers cat died a long time ago from malnutrition 2012-01-14T11:41:27 there is a chance I am still in a state of super position 2012-01-14T11:41:53 *** treeform has joined #aichallenge 2012-01-14T11:45:05 Somebody should've let him out of the box :( 2012-01-14T11:45:31 if someone can fix my calc 2012-01-14T11:45:36 I'm so out of here 2012-01-14T11:46:18 then go 2012-01-14T11:46:23 because some CAN fix it 2012-01-14T11:46:30 ? 2012-01-14T11:46:41 someone* 2012-01-14T11:46:45 it's in press-to-test mode 2012-01-14T11:47:11 reformatted it down to no OS 2012-01-14T11:47:16 still in test-to-press 2012-01-14T11:47:33 can't install the stupid official software on ubuntu 2012-01-14T11:47:41 don't have another calc 2012-01-14T11:48:39 Colors: in the meantime use this http://maxima.sourceforge.net/ 2012-01-14T11:48:50 bye 2012-01-14T11:50:16 this looks like a LISP spinoff 2012-01-14T11:50:31 so? 2012-01-14T11:50:44 it is lisp in the inside 2012-01-14T11:50:53 so I'll either use clisp for lambda calc 2012-01-14T11:51:20 or matlab for useful math 2012-01-14T11:51:30 *** TheLinker has joined #aichallenge 2012-01-14T11:51:57 lisp belongs in the CS museum 2012-01-14T11:51:58 *** Redgis has joined #aichallenge 2012-01-14T11:52:37 it's intended for it's own CPU architecture, not used for decades 2012-01-14T11:52:56 haha 2012-01-14T11:53:13 you bring wide smiles to my face 2012-01-14T11:53:16 I use lisp sometimes... for my gui, it's called sawfish 2012-01-14T11:54:10 you know what, I have a calculator made by MIT, I'll just use that for now 2012-01-14T11:57:24 https://www.boocoo.com/auction/uploaded/2011-3-7/ab215da72D0aa62D4ae72Db75f2Dace98a241379boocoo100.JPG 2012-01-14T11:58:27 Z_i leftarrow forall_i{({a_i owns X} = {Y owns b_i})} newline 2012-01-14T11:58:27 newline 2012-01-14T11:58:27 {sum from i = 1 to N(X_k)} and {sum from a=1 to N(Y_k)} 2012-01-14T11:59:03 *** amstan has joined #aichallenge 2012-01-14T11:59:03 *** ChanServ sets mode: +o amstan 2012-01-14T12:04:01 anyone here support latex? 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