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I see myself as a beginner and the only thing I learned abotu programming are from two years of programming class in high school. 2012-08-06T08:34:05 That's more than enough to start 2012-08-06T08:34:26 bobo: well, you won't win the challenge but any skill level can compete, have fun and learn something from it 2012-08-06T08:34:35 Well, considering what a high school programming level implies might be just enough 2012-08-06T08:35:33 it's not that I hope to win or climb the rankings, I'm jsut trying to have some fun and get experience, but I worry that I might be totally overwhelmed by the matter and fail totally. 2012-08-06T08:36:00 Nah, it's pretty good for beginners 2012-08-06T08:36:19 At least in Python and Java? 2012-08-06T08:36:55 thanks. I guess, I'll be okay. my second question is, how can I compete or try my bots. The Sign up is closed and I don't have an account. 2012-08-06T08:37:20 The competition ended in december last year 2012-08-06T08:37:30 And the next one has no start date set 2012-08-06T08:37:33 bobo: with that attitude (fun & improvement) you'lll be fine 2012-08-06T08:38:23 I know that the competition ended, but I want to try the bots by myself and see how they work. There must be some ways like offline matches, right? 2012-08-06T08:38:33 Sure 2012-08-06T08:38:52 There are some bots available online 2012-08-06T08:39:14 And a couple fairly stupid ones in the starter package 2012-08-06T08:40:00 great :) Then I'll read some tutorials and get into the matter. If I don't need an account, it'll be alright, I guess. 2012-08-06T08:40:25 thanks to you two. you helped me a lot! Have a great day :) 2012-08-06T08:40:42 You too 2012-08-06T08:42:53 *** bobo has quit IRC (Quit: Page closed) 2012-08-06T08:55:02 *** pairofdice has quit IRC (Quit: In girum imus nocte et consumimur igni.) 2012-08-06T09:23:45 first year logic, given a matrix A, since AA^T is symmetric we can conclude any matrix multiplied by its transpose is symmetric. 2012-08-06T09:50:10 *** mcstar has joined #aichallenge 2012-08-06T10:10:55 *** Guest64636 has quit IRC (Quit: Page closed) 2012-08-06T10:12:55 *** Surya has joined #aichallenge 2012-08-06T10:13:19 *** Surya is now known as Guest28694 2012-08-06T10:14:19 Hey there, I have a hard time identifying myself in this chan. My nick is Surya on the website. I do the /msg NickServ identify MYPWD. 2012-08-06T10:14:28 And it says : -NickServ- Invalid password for ayrus. 2012-08-06T10:14:54 Passwords are different between website and here I guess? 2012-08-06T10:18:00 *** mceier has quit IRC (Quit: leaving) 2012-08-06T10:21:23 You mean the aichallenge.org website? 2012-08-06T10:21:51 type "/nick MYNICK" to set your nick here 2012-08-06T10:26:32 I got a Surya Nick/channel is temporarily unavailable, ill try again later. Thx aerique 2012-08-06T10:42:46 *** kilae has joined #aichallenge 2012-08-06T10:47:10 mcstar: http://oeis.org/A058870 i think that's going to be useful to me in the future 2012-08-06T10:50:04 i really hope i conjecture 346 when i have 7 points across the top 2012-08-06T10:50:33 i got 1, 4, 18, 77 when i did 3-6 2012-08-06T10:50:46 hence above :P 2012-08-06T10:51:15 well, i know 3-5, n=6 and above is obviously a pita to generate by hand 2012-08-06T10:52:35 *** heinrich5991 has quit IRC (Ping timeout: 246 seconds) 2012-08-06T10:53:33 *** mcstar has quit IRC (*.net *.split) 2012-08-06T10:53:33 *** epicmonkey has quit IRC (*.net *.split) 2012-08-06T10:53:33 *** just4dos has quit IRC (*.net *.split) 2012-08-06T10:53:33 *** sevikkk has quit IRC (*.net *.split) 2012-08-06T10:53:34 *** CIA-26 has quit IRC (*.net *.split) 2012-08-06T10:53:40 *** heinrich5991 has joined #aichallenge 2012-08-06T10:54:14 *** amstan has joined #aichallenge 2012-08-06T10:54:14 *** ChanServ sets mode: +o amstan 2012-08-06T10:54:48 scratch that 2012-08-06T10:54:53 77 is wrong 2012-08-06T10:56:09 *** mcstar has joined #aichallenge 2012-08-06T10:56:09 *** just4dos has joined #aichallenge 2012-08-06T10:56:09 *** epicmonkey has joined #aichallenge 2012-08-06T10:56:09 *** sevikkk has joined #aichallenge 2012-08-06T10:56:09 *** CIA-26 has joined #aichallenge 2012-08-06T11:24:57 *** amstan has quit IRC (Quit: Konversation terminated!) 2012-08-06T11:40:53 antimatroid: whats that sequence? 2012-08-06T11:48:07 which one? 2012-08-06T11:48:09 the one i linked? no idea 2012-08-06T11:48:23 i'm looking for the number of elements in my diagram semigroups 2012-08-06T11:48:31 when i have a fixed number of nodes along the top 2012-08-06T11:48:39 i know it goes 1,4,18,... 2012-08-06T11:48:45 not sure what comes next exactly yet 2012-08-06T11:49:09 i'm pretty sure i know what diagrams are or aren't feasible 2012-08-06T11:49:14 just a pita to actually count htem 2012-08-06T11:49:31 antimatroid: nick me too 2012-08-06T11:49:45 is this the same problem as before? 2012-08-06T11:49:46 mcstar: my name is nick, that was confusing 2012-08-06T11:49:46 *** mceier has joined #aichallenge 2012-08-06T11:49:54 umm, similar 2012-08-06T11:49:59 the numbers are different 2012-08-06T11:50:03 it's taking those trident generators 2012-08-06T11:50:08 they generate a semigroup 2012-08-06T11:53:57 mcstar; http://sketchia.com/draw.html#8SaceTa 2012-08-06T11:54:10 the top left diagram is a "generator" when there's 5 top nodes 2012-08-06T11:54:40 basically the generators have the triapse adjacent then lines joining nodes from top to bottom 2012-08-06T11:54:59 to do the product of two diagrams you put one below the other and forget the middle nodes 2012-08-06T11:55:21 if there's a path joining a top node to a bottom node then they're part of the same hyperedge 2012-08-06T11:56:25 i am pretty sure starting from the generators you can get to the diagrams such that if a (hyper)edge connects a nodes along the top then it has to connect something in [a]_3 nodes along the bottom 2012-08-06T11:56:36 two examples of valid diagrams that can be generated are there 2012-08-06T11:56:42 then it's a matter of counting those feasible diagrams 2012-08-06T11:56:48 then i have to work out the structure for all this 2012-08-06T12:03:54 http://sketchia.com/draw_YUzvFmz.html 2012-08-06T12:15:30 i don't understand the love for that show 2012-08-06T12:18:18 http://www.london2012.com/news/articles/new-zealand-book-semi-final-berth.html 2012-08-06T12:18:20 birth* 2012-08-06T12:23:20 what show? 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